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See the recommended documentation of this function
histc
computes an histogram
Syntax
h = histc(n, data) h = histc(x, data) h = histc(.., normalization)
Arguments
- n
positive integer (number of classes)
- x
increasing vector defining the classes (
x
may have at least 2 components)- data
vector (data to be analysed)
- h
If
normalization
is %T: Probability densities on the bins defined byn
orx
, such that the bins areas are proportionnal to their populations.If
normalization
is %F: Numbers of elements in the bins.
- normalization
scalar boolean (default = %T), setting the type of output (see
h
).
Description
This function computes a histogram of the data
vector using the
classes x
. When the number n
of classes is provided
instead of x
, the classes are chosen equally spaced and
x(1) = min(data) < x(2) = x(1) + dx < ... < x(n+1) = max(data)
with dx = (x(n+1)-x(1))/n.
The classes are defined by C1 = [x(1), x(2)]
and Ci = ( x(i), x(i+1)]
for i >= 2.
Noting Nmax
the total number of data
(Nmax = length(data))
and Ni
the number of data
components falling in
Ci
, the value of the histogram for x
in
Ci
is equal to Ni/(Nmax (x(i+1)-x(i))) when
"normalized"
is selected and else, simply equal to Ni.
When normalization occurs the histogram verifies:
when x(1)<=min(data) and max(data) <= x(n+1)
Examples
- Example #1: variations around a histogram of a gaussian random sample
// The gaussian random sample d = rand(1, 10000, 'normal'); h = histc(20, d, normalization=%f); sum(h) // = 10000 // We use histplot to show a graphic representation clf(); histplot(20, d, normalization=%f); // Normalized histogram (probability density) h = histc(20, d); dx = (max(d)-min(d))/20; sum(h)*dx // = 1 clf(); histplot(20, d);
- Example #2: histogram of a binomial (B(6,0.5)) random sample
- Example #3: histogram of an exponential random sample
- Example #4: the frequency polygon chart and the histogram of a gaussian random sample
See also
History
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