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See the recommended documentation of this function

Scilab help >> Elementary Functions > bitwise > bitand

bitand

ビット単位の論理積(AND)

呼び出し手順

z = bitand(x,y)

パラメータ

x :

m行n列の行列(double)またはm1 x m2 x ... x mm ハイパー行列(double) または符合なし整数(uint8, uint16 または uint32)の m行n列行列.値は正の整数値である必要があります.

y :

m行n列の行列(double)またはm1 x m2 x ... x mm ハイパー行列(double) または符合なし整数(uint8, uint16 または uint32)の m行n列行列.値は正の整数値である必要があります.

z :

m行n列の行列(double)またはm1 x m2 x ... x mm ハイパー行列(double) または符合なし整数.

説明

2つの正の整数 x および y を指定すると,この関数は2進形式が x および y の2進形式の論理積となるような10進数を返します.

x, y, z の大きさは同じです.

// '1010110' : is the binary representation of 86 
// '1011011' : is the binary representation of 91   
// '1010010' : is the binary representation for the AND of binary representation 86 and 91 
// so the decimal number corresponding to the AND  applied to binary forms 86 and 91 is : 82
x=86; 
y=91;
z=bitand(x,y)

// Compute the bitwise AND of two matrices of doubles.
x=[12,45];
y=[25,49];
z=bitand(x,y)

// Compute the bitwise AND of two matrices of doubles.
x = [0 1 0 1];
y = [0 0 1 1];
z = bitand(x, y)
expected = [0 0 0 1];

// Compute the bitwise AND of two matrices of integers.
x = uint8([0 1 0 1]);
y = uint8([0 0 1 1]);
z = bitand(x, y)

// The types of x and y cannot be mixed (error).
x = [0 1 0 1];
y = uint8([0 0 1 1]);
// z = bitand(x, y)

//  13 is (01101)_2
//  27 is (11011)_2
// AND is (01001)_2 which is 9.
bitand(uint8(13), uint8(27))
bitand(13, 27)

参照

  • bitor — ビット単位の論理和(OR)
  • bin2dec — 2進表現を整数に変換します
  • dec2bin — 2進表現
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Last updated:
Mon Oct 01 17:40:22 CEST 2012