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See the recommended documentation of this function
bitand
bitwise AND
Calling Sequence
z = bitand(x, y)
Parameters
- x :
a
m
-by-n
matrix of doubles or am1
-by-m2
-by-...-by-mm
hypermatrix of doubles or am
-by-n
matrix of unsigned integers (uint8
,uint16
oruint32
). Must contain positive integer values.- y :
a
m
-by-n
matrix of doubles or am1
-by-m2
-by-...-by-mm
hypermatrix of doubles or am
-by-n
matrix of unsigned integers (uint8
,uint16
oruint32
).- z :
a
m
-by-n
matrix of doubles or am1
-by-m2
-by-...-by-mm
hypermatrix of doubles or am
-by-n
matrix of unsigned integers.
Description
Given x
and y
two positive integers, this function returns the decimal
number z
whose the binary form is the AND of the binary representations
of x
and y
.
x
, y
, z
have the same size.
Examples
// '1010110' : is the binary representation of 86 // '1011011' : is the binary representation of 91 // '1010010' : is the binary representation for the AND of binary representation 86 and 91 // so the decimal number corresponding to the AND applied to binary forms 86 and 91 is : 82 x=86; y=91; z=bitand(x,y) // Compute the bitwise AND of two matrices of doubles. x=[12,45]; y=[25,49]; z=bitand(x,y) // Compute the bitwise AND of two matrices of doubles. x = [0 1 0 1]; y = [0 0 1 1]; z = bitand(x, y) expected = [0 0 0 1]; // Compute the bitwise AND of two matrices of integers. x = uint8([0 1 0 1]); y = uint8([0 0 1 1]); z = bitand(x, y) // The types of x and y cannot be mixed (error). x = [0 1 0 1]; y = uint8([0 0 1 1]); // z = bitand(x, y) // 13 is (01101)_2 // 27 is (11011)_2 // AND is (01001)_2 which is 9. bitand(uint8(13), uint8(27)) bitand(13, 27)
See Also
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