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Aide Scilab >> Structures > cell

cell

creates a cell array of empty matrices

Calling Sequence

c = cell()
c = cell(m1)
c = cell(m1, m2)
c = cell(m1, m2, ..., mn)
c = cell(x)

Arguments

x

a vector containing the dimensions of the cell to create.

m1, m2, ..., mn

dimensions of the cell to create.

Description

cell returns a cell array of empty matrices.

cell()

returns a (0, 0) cell array of empty matrices.

cell(m1)

returns a (m1, m1) cell array of empty matrices.

cell(m1, m2)

returns a (m1, m2) cell array of empty matrices.

cell(m1,m2,..,mn)

creates a (m1, m2, ..., mn) cell array of empty matrices.

cell(x)

returns a cell array of empty matrices with: the first dimension of the cell array is x(1), the second dimension is x(2) and so on.

Remarks

cell(x) is not the same size that x.

cell() is equivalent to cell(0).

If A is a cell array, you can access the contents of an element of A by using A(m1, m2, ..., mn).entries. The expression A(1,1) = zeros(2,2) is not valid, the right syntax is A(1,1).entries = zeros(2,2).

If A is a cell array, you can get its dimensions by using A.dims which returns an int32 value that cannot be used as a subscript for the cell array. In this case, the best way to get the cell array dimensions is size(A).

Examples

a=cell(3)
b=cell(3,1)
c=cell([2,3,4])
 
// Assigning cell entries
b=cell(3,1);
 
// Assigning the first element of b using the 'entries' field
b(1).entries=1:3
 
// Assigning the second element of b using the 'entries' field
b(2).entries='Scilab'
 
// Assigning the third element of b using the 'entries' field
b(3).entries=poly(1:3,'s')
 
// Assigning sub-cells
X=cell(3,2);
X(:,1)=b
 
// Extracting a sub-cell: result is a cell
b(1)
b(1:2)
 
// Extracting a sub-cell value: result is an array
b(1).entries
 
// Dimensions of b as an int32 value (cannot be used as an index)
b.dims
// Dimensions of b as a double value
size(b)

See Also

  • eye — matrice identité
  • ones — matrice remplie de 1
  • zeros — matrice nulle
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Last updated:
Tue Apr 02 17:36:47 CEST 2013