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Aide Scilab >> Fonctions avancées > varargin

# varargin

variable numbers of arguments in an input argument list

### Description

A function whose last input argument is `varargin` can be called with more input arguments than indicated in the input argument list. The calling arguments passed form `varargin` keyword onwards may then be retrieved within the function in a list named `varargin`.

Suppose that `varargin` keyword is the `n` th argument of the formal input argument list, then if the function is called with less than `n-1` input arguments the `varargin` list is not defined, if the function is called with `n-1` arguments then `varargin` list is an empty list.

`y= function ex(varargin)` may be called with any number of input arguments. Within function `ex` input arguments may be retrieved in `varargin(i)` ,`i=1:length(varargin)`

If it is not the last input argument of a function, `varargin` is a normal input argument name with no special meaning.

The total number of actual input arguments is given by argn(2).

### Remark

Named argument syntax like `foo(...,key=value)` is incompatible with the use of varargin. The reason is that the names (i.e. keys) associated with values are not stored in the varargin list. Consider for instance:

function foo(varargin),disp([varargin(1),varargin(2)]),endfunction

foo(a=1,b=2)

foo(b=1,a=2)

Result is the same, but the arguments were inverted.

### Examples

```deff('exampl(a,varargin)',['[lhs,rhs]=argn(0)'
'if rhs>=1 then disp(varargin),end'])
exampl(1)
exampl()
exampl(1,2,3)
l=list('a',%s,%t);
exampl(1,l(2:3))```