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Scilab help >> Elementary Functions > bitwise > bitor

bitor

ビット単位の論理和(OR)

呼び出し手順

z = bitor(x,y)

パラメータ

x :

m行n列の行列(double)またはm1 x m2 x ... x mm ハイパー行列(double) または符合なし整数(uint8, uint16 または uint32)の m行n列行列.値は正の整数値である必要があります.

y :

m行n列の行列(double)またはm1 x m2 x ... x mm ハイパー行列(double) または符合なし整数(uint8, uint16 または uint32)の m行n列行列.値は正の整数値である必要があります.

z :

m行n列の行列(double)またはm1 x m2 x ... x mm ハイパー行列(double) または符合なし整数.

説明

2つの正の整数 x および y を指定すると,この関数は2進形式が x および y の2進形式の論理和となるような10進数を返します.

x, y, z の大きさは同じです.

// '110000' : is the binary representation of 48 
// '100101' : is the binary representation of 37   
// '110101' : is the binary representation for the OR applied to the binary forms 48 and 37 
// so the decimal number corresponding to the OR  applied to binary forms 48 and 37 is : 53
x=48; 
y=37;
z=bitor(x,y)

// Compute the bitwise OR of two matrices of doubles.
x=[12,45]; 
y=[25,49];
z=bitor(x,y)

// Compute the bitwise OR of two matrices of doubles.
x = [0 1 0 1];
y = [0 0 1 1];
z = bitor(x, y)
expected = [0 1 1 1];

// Compute the bitwise OR of two matrices of integers.
x = uint8([0 1 0 1]);
y = uint8([0 0 1 1]);
z = bitor(x, y)

// The types of x and y cannot be mixed (error).
x = [0 1 0 1];
y = uint8([0 0 1 1]);
z = bitor(x, y)

//  13 is (01101)_2
//  27 is (11011)_2
//  OR is (11111)_2 which is 31.
bitor(uint8(13), uint8(27))
bitor(13, 27)

作者

  • Copyright (C) 2011 - DIGITEO - Michael Baudin
  • Copyright (C) INRIA - Farid BELAHCENE
  • Copyright (C) 2008 - INRIA - Pierre MARECHAL

参照

  • bitand — ビット単位の論理積(AND)
  • bin2dec — 2進表現を整数に変換します
  • dec2bin — 2進表現
<< bitget bitwise bitset >>

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Last updated:
Wed Oct 05 12:12:38 CEST 2011