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5.3.2 - 日本語

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See the recommended documentation of this function

Scilab help >> GUI > Tree > uiDeleteNode

uiDeleteNode

Deletion in a Tree

Calling Sequence

delTree = uiDeleteNode(tree, node)
delTree = uiDeleteNode(tree, position)

Input parameters

tree

Tree were we do the deletion

node

node we want to delete

position

a string, which is the position of the node we want to delete

Output parameters

delTree

a Tree without the deleted node

Description

Deletion of a node (subTree) from a tree. If we have 3 nodes called 'Node1', 'Node2' and 'Node3' each one at position 1.1, 1.2, and 1.3. Deletion of node at position 1.2 ('Node2') will pull up the 'Node 3' to position 1.2.

Examples

// We should create nodes(subTrees) before creating trees	
leaf11 = uiCreateNode('leaf 1.1', 'iconLeaf1.1', 'callbackLeaf1.1')
leaf12 = uiCreateNode('leaf 1.2', 'iconLeaf1.2', 'callbackLeaf1.2')
leaf31 = uiCreateNode('leaf 3.1', 'iconLeaf3.1', 'callbackLeaf3.1')
leaf32 = uiCreateNode('leaf 3.2', 'iconLeaf3.2', 'callbackLeaf3.2')
node1 = uiCreateNode('Node 1', 'iconNode1', 'callbackNode1')
node2 = uiCreateNode('Node 2', 'iconNode2', 'callbackNode2')
node3 = uiCreateNode('Node 3', 'iconNode3', 'callbackNode3')
root = uiCreateNode('Root', 'iconRoot', 'callbackRoot')

treeNode1 = uiCreateTree(node1, leaf11, leaf12)
treeNode3 = uiCreateTree(node3, leaf31, leaf32)
treeRoot = uiCreateTree(root, treeNode1, node2, treeNode3)

// Deletion of 'node2'
treeDel = uiDeleteNode(treeRoot, node2)
uiDisplayTree(treeDel)

// Deletion of node at position '3.2'
treeDel = uiDeleteNode(treeRoot, '3.2')
uiDisplayTree(treeDel)

See Also

<< uiCreateTree Tree uiDisplayTree >>

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Last updated:
Thu May 12 11:45:57 CEST 2011