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2024.1.0 - English


uiGetNodePosition

Get the position(s) of a node

Syntax

position = uiGetNodePosition(tree, node)

Input parameters

tree

uitree in which we look for position(s) of a node

node

the node we look for position(s)

Output parameters

position

a matrix of string which contains node position(s).

Description

Get the position of a given node.

Examples

// We should create nodes(subTrees) before creating trees
leaf11 = uiCreateNode('leaf 1.1', 'iconLeaf1.1', 'callbackLeaf1.1')
leaf12 = uiCreateNode('leaf 1.2', 'iconLeaf1.2', 'callbackLeaf1.2')
leaf31 = uiCreateNode('leaf 3.1', 'iconLeaf3.1', 'callbackLeaf3.1')
leaf32 = uiCreateNode('leaf 3.2', 'iconLeaf3.2', 'callbackLeaf3.2')
node1 = uiCreateNode('Node 1', 'iconNode1', 'callbackNode1')
node2 = uiCreateNode('Node 2', 'iconNode2', 'callbackNode2')
node3 = uiCreateNode('Node 3', 'iconNode3', 'callbackNode3')
root = uiCreateNode('Root', 'iconRoot', 'callbackRoot')

treeNode1 = uiCreateTree(node1, leaf11, leaf12)
treeNode3 = uiCreateTree(node3, leaf31, leaf32)
treeRoot = uiCreateTree(root, treeNode1, node2, treeNode3)

// Get the position of node 'node1'
position = uiGetNodePosition(treeRoot, node1)
// will return 'position = ['1']'

// Get the position of leaf 'leaf31'
position = uiGetNodePosition(treeRoot, leaf31)
// will return 'position = ['3.1']'

See also

Report an issue
<< uiGetChildrenNode uitree uiGetParentNode >>

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Last updated:
Mon Jun 17 17:49:17 CEST 2024