bitand

Parameters

x :

a m-by-n matrix of doubles or a m1-by-m2-by-...-by-mm hypermatrix of doubles or a m-by-n matrix of unsigned integers (uint8, uint16 or uint32). Must contain positive integer values.

y :

a m-by-n matrix of doubles or a m1-by-m2-by-...-by-mm hypermatrix of doubles or a m-by-n matrix of unsigned integers (uint8, uint16 or uint32).

z :

a m-by-n matrix of doubles or a m1-by-m2-by-...-by-mm hypermatrix of doubles or a m-by-n matrix of unsigned integers.

Description

Given x and y two positive integers, this function returns the decimal number z whose the binary form is the AND of the binary representations of x and y.

x, y, z have the same size.

Examples

// '1010110' : is the binary representation of 86 
// '1011011' : is the binary representation of 91   
// '1010010' : is the binary representation for the AND of binary representation 86 and 91 
// so the decimal number corresponding to the AND  applied to binary forms 86 and 91 is : 82
x=86; 
y=91;
z=bitand(x,y)

// Compute the bitwise AND of two matrices of doubles.
x=[12,45];
y=[25,49];
z=bitand(x,y)

// Compute the bitwise AND of two matrices of doubles.
x = [0 1 0 1];
y = [0 0 1 1];
z = bitand(x, y)
expected = [0 0 0 1];

// Compute the bitwise AND of two matrices of integers.
x = uint8([0 1 0 1]);
y = uint8([0 0 1 1]);
z = bitand(x, y)

// The types of x and y cannot be mixed (error).
x = [0 1 0 1];
y = uint8([0 0 1 1]);
// z = bitand(x, y)

//  13 is (01101)_2
//  27 is (11011)_2
// AND is (01001)_2 which is 9.
bitand(uint8(13), uint8(27))
bitand(13, 27)

See Also

• bitor — bitwise OR
• bin2dec — convert from binary to decimal
• dec2bin — convert from decimal to binary