for
keyword entering a non-conditional loop
Syntax
for variable = expression, instruction ; .. ; instruction; end for variable = expression instruction .. instruction end for variable = expression do instruction, .. instruction end
Description
If expression is an array (homogeneous or not), variable
            is set to each of its columns (for a hypermatrix, as
            matrix(expression, size(expression,1), -1))), one by one.
A particular case uses the colon operator to create regularly
            spaced row vectors, and is similar to traditional for loop forms:
            for variable = n1:step:n2, ...,end
If expression is a list, variable takes as values the
            successive entries of the list.
According to the Code Conventions for the Scilab Programming Language it is recommended:
- Start each statement on a new line. 
- Write no more than one simple statement per line. 
- Break compound statements over multiple lines. 
For example, preferably use:
for i = 1:5 disp(i); end
rather than:
for i = 1:5, disp(i); end
Examples
Trivial iterations (over columns of a row vector):
for i = [2 4 5] factorial(i) end // By decreasing values: for j = 4:-1:1 j end
Iterate on the columns of a matrix:
M = [1 2 ; 3 4 ; 5 6]' for c = M, c, end
-> M = [1 2 ; 3 4 ; 5 6]' M = 1. 3. 5. 2. 4. 6. --> for c = M, c, end c = 1. 2. c = 3. 4. c = 5. 6.
Iterate on the columns of a cell array:
C = {%pi, "This is πι" ; %z^2, %t} for c = C, c, end
--> C = {%pi, "This is πι" ; %z^2, %t}
 C  =
  [1x1 constant  ]  [1x1 string ]
  [1x1 polynomial]  [1x1 boolean]
--> for  c = C, c, end
 c  =
  [1x1 constant  ]
  [1x1 polynomial]
 c  =
  [1x1 string ]
  [1x1 boolean]
Loop on the elements of a list:
for l = list([1 2;3 4], (1+%z)^3, 'example', [%F %T]); l, end
--> for l = list([1 2;3 4], (1+%z)^3, 'example', [%F %T]); l, end
 l  =
   1.   2.
   3.   4.
 l  =
            2   3
   1 +3z +3z  +z
 l  =
 example
 l  =
  F T
Common and nested loops:
See also
History
| Version | Description | 
| 6.0.0 | 
 | 
| 2023.0.0 | The expressioncan be a hypermatrix. It is then processed
                    by column asmatrix(expression, size(expression,1), -1). | 
| Report an issue | ||
| << end | Control flow | halt >> |